How are champion matchup win rates calculated?

Win rates are calculated from thousands of ranked games in Emerald+ elo on the current patch. Data is sourced from OP.GG and updated regularly.

What does a 55% win rate matchup mean?

A 55% win rate means Champion 1 wins 55 out of every 100 games against Champion 2 in ranked. Anything above 52% is considered a favorable matchup.

Do matchup win rates change every patch?

Yes. Champion buffs, nerfs, item changes, and meta shifts can all affect matchup win rates. Our data updates with each new patch.

Should I always pick the counter champion?

Not necessarily. Comfort and experience on a champion often matter more than counter-picking, especially below Diamond. A 2-3% win rate difference is easily overcome by champion mastery.

What rank is the matchup data from?

All matchup data is sourced from Emerald+ ranked games to ensure the data reflects skilled play. Lower elo matchups can differ significantly.

Patch 26.9 Data

Champion Matchups

Pick two champions and see who wins. Win rates, counters, and tips powered by live ranked data.

Champion 1

Kayn

Champion 2

Zac

51.4%

Kayn win rate vs Zac

Skill matchup — could go either way

630

Games Analyzed

51.4%

Kayn WR

48.6%

Zac WR

+114

Avg Gold Diff @15

Power Spike Timeline

Zac Level 3

Kayn Level 6

Zac Level 6

Kayn 1 item

Kayn Form transform

Zac 2 items

How to Play This Matchup

Mid-Game Showdown

Both champions spike around the same time. The player who gets their first item faster wins. Focus on CS leads and smart trades to build an advantage before the mid-game.

Mixed Resistances

Kayn deals AD damage while Zac deals AP. Build resistances accordingly Ã¢â‚¬â€ don't stack the wrong type.

Exploit Zac's Weakness

Zac's main weakness: Grievous wounds, burst before blobs, invades early. Play around this to maximize your advantage.

Kayn Win Condition

Transform into assassin or drain tank, wall walk ganks

Zac Win Condition

Long-range E engage, R displacement, blob passive revive

Recommended Items

Kayn